107期2478=01開415對(duì)
108期3569=01開758對(duì)
109期3578=01開474對(duì)
110期0278=01開988對(duì)
111期4689=01開871對(duì)
112期3578=01開451對(duì)
113期2569=01開405對(duì)
114期2569=01開844對(duì)
115期2478=01開598對(duì)
116期4689=01開771對(duì)
117期0358=01開716對(duì)
118期2478=01開607對(duì)
119期2478=01開079對(duì)
120期3679=01開748對(duì)
121期3578=01開227對(duì)
122期4689=01開274對(duì)
123期0278=01開240錯(cuò)
124期2478=01開599對(duì)
125期1356=01開259對(duì)
126期3578=01開971對(duì)
127期3679=01開097錯(cuò)
128期3679=01開313對(duì)
129期3578=01開055對(duì)
130期3679=01開218對(duì)
131期0278=01開471對(duì)
132期0278=01開685對(duì)
133期4568=01開001對(duì)
134期4568=01開661對(duì)
135期0278=01開231對(duì)
我只能看出應(yīng)該是固定的4碼卻怎么也破解不出來是什么對(duì)應(yīng)的
破解方法就是上期開獎(jiǎng)號(hào)和尾加跨度的得數(shù)取個(gè)位對(duì)應(yīng)4碼=01
0--2478  1--0358  2--4568  3--3578  4--2569
5--3679  6--4689  7--1356  8--0278  9--3578

例如134期開661 和尾3 跨度5 3加5就等于8
8對(duì)應(yīng)0278 那么135期對(duì)應(yīng)4碼0278=01
其他期數(shù)開獎(jiǎng)號(hào)以此類推。